Math Problem Statement

Differentiate y = -4e^(-x) with respect to x.

Solution

Let's solve the given problem step by step.

Given:

y=4exy = -4e^{-x}

We need to calculate dydx\frac{dy}{dx}.


Step 1: Differentiate yy with respect to xx

Using the chain rule: ddx[4ex]=4ddx(ex)\frac{d}{dx} \left[ -4e^{-x} \right] = -4 \cdot \frac{d}{dx} \left( e^{-x} \right)

The derivative of exe^{-x} is ex-e^{-x}, so: dydx=4(ex)=4ex\frac{dy}{dx} = -4 \cdot (-e^{-x}) = 4e^{-x}


Step 2: Simplify

Since exe^{-x} is the reciprocal of exe^x, we can rewrite the result as: dydx=4ex\frac{dy}{dx} = \frac{4}{e^x}


Step 3: Match the options

The correct answer is: a. 4ex\frac{4}{e^x}

Let me know if you'd like further clarification! 😊


Follow-up Questions:

  1. What is the chain rule and when do we use it in differentiation?
  2. How does the exponential function exe^x behave as xx \to \infty and xx \to -\infty?
  3. Why is the derivative of exe^{-x} equal to ex-e^{-x}?
  4. What does the derivative of y=4exy = -4e^{-x} represent in a graph?
  5. How would the derivative change if y=4exy = -4e^{x}?

Tip:

Always simplify exponential terms like exe^{-x} into fraction form 1/ex1/e^x when comparing options!

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Math Problem Analysis

Mathematical Concepts

Differentiation
Exponential Functions
Chain Rule

Formulas

d/dx[e^x] = e^x
Chain rule: d/dx[f(g(x))] = f'(g(x)) * g'(x)

Theorems

Chain rule for differentiation

Suitable Grade Level

Grades 11-12